当函数的参数不确定时,可以使用*args 和**kwargs,*args 没有key值,**kwargs有key值。还是直接来代码吧,废话少说
*args
def fun_var_args(farg, *args): print "arg:", farg for value in args: print "another arg:", value fun_var_args(1, "two", 3) # *args可以当作可容纳多个变量组成的list
result:文章源自运维生存时间-https://www.ttlsa.com/python/python-args-kwargs/
arg: 1 another arg: two another arg: 3
**kwargs:
def fun_var_kwargs(farg, **kwargs): print "arg:", farg for key in kwargs: print "another keyword arg: %s: %s" % (key, kwargs[key]) fun_var_kwargs(farg=1, myarg2="two", myarg3=3) # myarg2和myarg3被视为key, #感觉**kwargs可以当作容纳多个key和value的dictionary
result:文章源自运维生存时间-https://www.ttlsa.com/python/python-args-kwargs/
arg: 1 another keyword arg: myarg2: two another keyword arg: myarg3: 3
也可以用下面的形式
*args的另外一种方式文章源自运维生存时间-https://www.ttlsa.com/python/python-args-kwargs/
def fun_var_args_call(arg1, arg2, arg3): print "arg1:", arg1 print "arg2:", arg2 print "arg3:", arg3 args = ["two", 3] #list fun_var_args_call(1, *args)
result:文章源自运维生存时间-https://www.ttlsa.com/python/python-args-kwargs/
arg1: 1 arg2: two arg3: 3
**kwargs的另外一种方式文章源自运维生存时间-https://www.ttlsa.com/python/python-args-kwargs/
def fun_var_args_call(arg1, arg2, arg3): print "arg1:", arg1 print "arg2:", arg2 print "arg3:", arg3 kwargs = {"arg3": 3, "arg2": "two"} # dictionary fun_var_args_call(1, **kwargs)
result:文章源自运维生存时间-https://www.ttlsa.com/python/python-args-kwargs/
arg1: 1 arg2:"two" arg3:3
文章源自运维生存时间-https://www.ttlsa.com/python/python-args-kwargs/
文章源自运维生存时间-https://www.ttlsa.com/python/python-args-kwargs/ 文章源自运维生存时间-https://www.ttlsa.com/python/python-args-kwargs/

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无语,*args放在定义函数的时候是可变长序列,类型是元祖,**kw是可变长字典,在调用时却是解压序列或字典