SQL joins操作图:
设计两张表A和B,记录如下:文章源自运维生存时间-https://www.ttlsa.com/mysql/drawing-interpretation-of-sql-joint-statement/
id name id name -- ---- -- ---- 1 Pirate 1 Rutabaga 2 Monkey 2 Pirate 3 Ninja 3 Darth Vader 4 Spaghetti 4 Ninja
1. 内联合(inner join)只生成同时匹配表A和表B的记录集文章源自运维生存时间-https://www.ttlsa.com/mysql/drawing-interpretation-of-sql-joint-statement/
SELECT * FROM TableA INNER JOIN TableB ON TableA.name = TableB.name id name id name -- ---- -- ---- 1 Pirate 2 Pirate 3 Ninja 4 Ninja
图解如下:文章源自运维生存时间-https://www.ttlsa.com/mysql/drawing-interpretation-of-sql-joint-statement/
文章源自运维生存时间-https://www.ttlsa.com/mysql/drawing-interpretation-of-sql-joint-statement/
2. 全外联合(full outer join)生成表A和表B里的记录全集,包括两边都匹配的记录。如果有一边没有匹配的,缺失的这一边为null文章源自运维生存时间-https://www.ttlsa.com/mysql/drawing-interpretation-of-sql-joint-statement/
SELECT * FROM TableA FULL OUTER JOIN TableB ON TableA.name = TableB.name id name id name -- ---- -- ---- 1 Pirate 2 Pirate 2 Monkey null null 3 Ninja 4 Ninja 4 Spaghetti null null null null 1 Rutabaga null null 3 Darth Vader
图解如下:文章源自运维生存时间-https://www.ttlsa.com/mysql/drawing-interpretation-of-sql-joint-statement/
文章源自运维生存时间-https://www.ttlsa.com/mysql/drawing-interpretation-of-sql-joint-statement/
文章源自运维生存时间-https://www.ttlsa.com/mysql/drawing-interpretation-of-sql-joint-statement/
3. 左外联合(left outer join)生成表A的所有记录,包括在表B里匹配的记录。如果没有匹配的,右边将是null文章源自运维生存时间-https://www.ttlsa.com/mysql/drawing-interpretation-of-sql-joint-statement/
SELECT * FROM TableA LEFT OUTER JOIN TableB ON TableA.name = TableB.name id name id name -- ---- -- ---- 1 Pirate 2 Pirate 2 Monkey null null 3 Ninja 4 Ninja 4 Spaghetti null null
图解如下:文章源自运维生存时间-https://www.ttlsa.com/mysql/drawing-interpretation-of-sql-joint-statement/
文章源自运维生存时间-https://www.ttlsa.com/mysql/drawing-interpretation-of-sql-joint-statement/
文章源自运维生存时间-https://www.ttlsa.com/mysql/drawing-interpretation-of-sql-joint-statement/
为了生成只在表A里而不在表B里的记录集,我们用同样的左外联合,然后用where语句排除我们不想要的记录。文章源自运维生存时间-https://www.ttlsa.com/mysql/drawing-interpretation-of-sql-joint-statement/
SELECT * FROM TableA LEFT OUTER JOIN TableB ON TableA.name = TableB.name WHERE TableB.id IS null id name id name -- ---- -- ---- 2 Monkey null null 4 Spaghetti null null
图解如下:文章源自运维生存时间-https://www.ttlsa.com/mysql/drawing-interpretation-of-sql-joint-statement/
文章源自运维生存时间-https://www.ttlsa.com/mysql/drawing-interpretation-of-sql-joint-statement/
文章源自运维生存时间-https://www.ttlsa.com/mysql/drawing-interpretation-of-sql-joint-statement/
为了生成对于表A和表B唯一的记录集,我们用同样的全外联合,然后用where语句排除两边都不想要的记录。文章源自运维生存时间-https://www.ttlsa.com/mysql/drawing-interpretation-of-sql-joint-statement/
SELECT * FROM TableA FULL OUTER JOIN TableB ON TableA.name = TableB.name WHERE TableA.id IS null OR TableB.id IS null id name id name -- ---- -- ---- 2 Monkey null null 4 Spaghetti null null null null 1 Rutabaga null null 3 Darth Vader
图解如下:文章源自运维生存时间-https://www.ttlsa.com/mysql/drawing-interpretation-of-sql-joint-statement/
文章源自运维生存时间-https://www.ttlsa.com/mysql/drawing-interpretation-of-sql-joint-statement/ 文章源自运维生存时间-https://www.ttlsa.com/mysql/drawing-interpretation-of-sql-joint-statement/
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